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(A) $1$. Electronegativity trend: According to the Pauling scale, the electronegativity values are $F$ $(4.0)$, $O$ $(3.5)$, and $N$ $(3.0)$. Thus, th

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Both Statement $I$ and Statement $II$ are true

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(A) $1$. Electronegativity trend: According to the Pauling scale, the electronegativity values are $F$ $(4.0)$, $O$ $(3.5)$, and $N$ $(3.0)$. Thus, the order $F > O > N$ is correct. Statement $I$ is true.$2$. Oxidation states: In $OF_2$, fluorine is more electronegative than oxygen, so oxygen is $+2$. In $Na_2O$, sodium is $+1$, so oxygen is $-2$. Statement $II$ is true.Therefore, both statements are true.

Given below are two statements:
Statement $I$: The correct order of electronegativity of fluorine, oxygen and nitrogen is $F > O > N$.
Statement $II$: The oxidation state of oxygen in $OF_2$ is $+2$ and in $Na_2O$ is $-2$.

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Given below are two statements:Statement $I$: The correct order of electronegativity of fluorine, oxygen and nitrogen is $F > O > N$.Statement $II$: The oxidation state of oxygen in $OF_2$ is $+2$ and in $Na_2O$ is $-2$.