Given below is the plot of a potential energy | vedclass

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Question

(A) The total mechanical energy is $E_{	ext{mech}} = K.E. + U = 8 \, J$. $(A)$ At $x = x_{3}$,from the graph,$U = 4 \, J$. Therefore,$K.E. = E_{	ext

Vedclass · Accepted Answer

at $x = x_{3}$,$K.E. = 10 \, J$

Vedclass · Answer

(A) The total mechanical energy is $E_{	ext{mech}} = K.E. + U = 8 \, J$. $(A)$ At $x = x_{3}$,from the graph,$U = 4 \, J$. Therefore,$K.E. = E_{	ext{mech}} - U = 8 - 4 = 4 \, J$. The statement says $K.E. = 10 \, J$,which is incorrect. $(B)$ At $x = x_{2}$,from the graph,$U = 0 \, J$. Therefore,$K.E. = 8 - 0 = 8 \, J$. Since $U$ is minimum,$K.E.$ is maximum,and the particle moves at the fastest speed. This statement is correct. $(C)$ At $x $(D)$ At $x > x_{4}$,from the graph,$U = 6 \, J$ (constant). Therefore,$K.E. = 8 - 6 = 2 \, J$ (constant). This statement is also correct.

Given below is the plot of a potential energy function $U(x)$ for a system,in which a particle is in one-dimensional motion,while a conservative force $F(x)$ acts on it. Suppose that $E_{\text{mech}} = 8 \, J$,the incorrect statement for this system is:

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