(A) The cell reaction is: $2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$.This reaction consists of two half-reactions:Cathode (Reduction): $2Fe^{3+} + 2e^- \to

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(A) The cell reaction is: $2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$.This reaction consists of two half-reactions:Cathode (Reduction): $2Fe^{3+} + 2e^- \to 2Fe^{2+}$; $E^o_{\text{cathode}} = 0.771 \, V$.Anode (Oxidation): $2I^- \to I_2 + 2e^-$; $E^o_{\text{anode}} = 0.536 \, V$.$E^o_{\text{cell}} = E^o_{\text{cathode}} - E^o_{\text{anode}}$.$E^o_{\text{cell}} = 0.771 \, V - 0.536 \, V = 0.235 \, V$.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

Medium

Given electrode potentials:
$Fe^{3+} + e^- \to Fe^{2+}$; $E^o = 0.771 \, V$
$I_2 + 2e^- \to 2I^-$; $E^o = 0.536 \, V$
$E^o_{\text{cell}}$ for the cell reaction
$2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$ is:

A
$0.771 - 0.536 = 0.235 \, V$
B
$0.536 - 0.771 = -0.235 \, V$
C
$2 \times 0.771 - 0.536 = 1.006 \, V$
D
$0.771 + 0.536 = 1.307 \, V$

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Electrode potential and ECell

The standard electrode potentials of the half-cells are given below:
$Zn^{2+} + 2e^- \to Zn$; $E^{\circ} = -0.76 \, V$
$Fe^{2+} + 2e^- \to Fe$; $E^{\circ} = -0.44 \, V$
The $EMF$ of the cell $Fe^{2+} + Zn \to Zn^{2+} + Fe$ is ............ $V$.

Medium

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The standard reduction potential for $Fe^{2+}/Fe$ and $Sn^{2+}/Sn$ electrodes are $-0.44 \ V$ and $-0.14 \ V$ respectively. For the given cell reaction $Fe^{2+} + Sn \to Fe + Sn^{2+}$,the standard $EMF$ is ...............$V$.

MediumIIT 1990

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At $25^\circ C$,$1 \, atm$ of gas $X$ is bubbled through a solution containing $1 \, M$ $Y^-$ and $1 \, M$ $Z^-$. If the reduction potential order is $Z > Y > X$,then:

Easy

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The standard reduction potentials of three metals $A, B,$ and $C$ are $+0.5 \, V, -3.0 \, V,$ and $-1.2 \, V$ respectively. What is the order of their reducing power?

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The standard electrode potentials $\left( E_{M^{+}/M}^\circ \right)$ of four metals $A, B, C$ and $D$ are $-1.2 \ V, 0.6 \ V, 0.85 \ V$ and $-0.76 \ V$,respectively. The sequence of deposition of metals on applying potential is

DifficultJEE MAIN 2014

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Given electrode potentials:$Fe^{3+} + e^- \to Fe^{2+}$; $E^o = 0.771 \, V$$I_2 + 2e^- \to 2I^-$; $E^o = 0.536 \, V$$E^o_{\text{cell}}$ for the cell reaction$2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$ is:

Similar Questions

The standard electrode potentials of the half-cells are given below:$Zn^{2+} + 2e^- \to Zn$; $E^{\circ} = -0.76 \, V$$Fe^{2+} + 2e^- \to Fe$; $E^{\circ} = -0.44 \, V$The $EMF$ of the cell $Fe^{2+} + Zn \to Zn^{2+} + Fe$ is ............ $V$.

The standard reduction potential for $Fe^{2+}/Fe$ and $Sn^{2+}/Sn$ electrodes are $-0.44 \ V$ and $-0.14 \ V$ respectively. For the given cell reaction $Fe^{2+} + Sn \to Fe + Sn^{2+}$,the standard $EMF$ is ...............$V$.

At $25^\circ C$,$1 \, atm$ of gas $X$ is bubbled through a solution containing $1 \, M$ $Y^-$ and $1 \, M$ $Z^-$. If the reduction potential order is $Z > Y > X$,then:

The standard reduction potentials of three metals $A, B,$ and $C$ are $+0.5 \, V, -3.0 \, V,$ and $-1.2 \, V$ respectively. What is the order of their reducing power?

The standard electrode potentials $\left( E_{M^{+}/M}^\circ \right)$ of four metals $A, B, C$ and $D$ are $-1.2 \ V, 0.6 \ V, 0.85 \ V$ and $-0.76 \ V$,respectively. The sequence of deposition of metals on applying potential is

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Given electrode potentials:
$Fe^{3+} + e^- \to Fe^{2+}$; $E^o = 0.771 \, V$
$I_2 + 2e^- \to 2I^-$; $E^o = 0.536 \, V$
$E^o_{\text{cell}}$ for the cell reaction
$2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$ is:

The standard electrode potentials of the half-cells are given below:
$Zn^{2+} + 2e^- \to Zn$; $E^{\circ} = -0.76 \, V$
$Fe^{2+} + 2e^- \to Fe$; $E^{\circ} = -0.44 \, V$
The $EMF$ of the cell $Fe^{2+} + Zn \to Zn^{2+} + Fe$ is ............ $V$.