Given:Solution A: Phenol and anilineSolution | vedclass

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Question

(B) Solution $A$ (Phenol and aniline) shows negative deviation from Raoult's law because the intermolecular hydrogen bonding between phenol and anilin

Vedclass · Accepted Answer

Both solutions $A$ and $B$ show $-ve$ deviation

Vedclass · Answer

(B) Solution $A$ (Phenol and aniline) shows negative deviation from Raoult's law because the intermolecular hydrogen bonding between phenol and aniline molecules is stronger than the individual $A-A$ and $B-B$ interactions.Solution $B$ (Chloroform and acetone) also shows negative deviation because the formation of hydrogen bonding between the chloroform $(CHCl_3)$ and acetone $(CH_3COCH_3)$ molecules makes the $A-B$ interaction stronger than the $A-A$ and $B-B$ interactions.Therefore, both solutions $A$ and $B$ show $-ve$ deviation.

Given:
Solution $A$: Phenol and aniline
Solution $B$: Chloroform and acetone
Which of the following is correct as per Raoult's law?

Similar Questions

When does a mixture containing components $A$ and $B$ show negative deviation from Raoult's law?

Which of the following are correct for an ideal solution?
$(a) \Delta V_{\text{mix}} = 0$
$(b) V_{\text{solvent}} + V_{\text{solute}} = V_{\text{solution}}$
$(c) \Delta H_{\text{mix}} = 0$
$(d) H_2O + CO_2 \rightarrow H_2CO_3$ is an example of an ideal solution.

Identify the false statement among the following.

An ideal solution has two components $A$ and $B$. If $A$ is more volatile than $B$,then the correct relation between mole fraction of $A$ in liquid $(X_A)$ and vapour phase $(Y_A)$ is:

The solution which shows negative or positive deviation from Raoult's law is called:

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Given:Solution $A$: Phenol and anilineSolution $B$: Chloroform and acetoneWhich of the following is correct as per Raoult's law?