The government has divided the frequency rang | vedclass

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Question

(B) The total frequency range available is $60\ MHz - 30\ MHz = 30\ MHz$.There are $20$ stations sharing this range.Therefore,the bandwidth available

Vedclass · Accepted Answer

Music signals and voice signals only

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(B) The total frequency range available is $60\ MHz - 30\ MHz = 30\ MHz$.There are $20$ stations sharing this range.Therefore,the bandwidth available for each station is $\Delta f = \frac{30\ MHz}{20} = 1.5\ MHz$.Voice signals typically require a bandwidth of $3\ kHz$,and music signals require about $15\ kHz$.$TV$ signals require a bandwidth of $6\ MHz$ for transmission.Since each station has a bandwidth of $1.5\ MHz$,it can accommodate voice signals $(3\ kHz)$ and music signals $(15\ kHz)$,but it cannot accommodate a standard $TV$ signal $(6\ MHz)$.Thus,each station can beam voice and music signals.

List-$I$	List-$II$
$A$. Television signal	$I$. $03\,KHz$
$B$. Radio signal	$II$. $20\,KHz$
$C$. High Quality Music	$III$. $02\,MHz$
$D$. Human speech	$IV$. $06\,MHz$

The government has divided the frequency range from $30\ MHz$ to $60\ MHz$ between $20$ stations,which are independently beaming their signals. Which of the signals can be beamed by each of the stations?

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Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A$. Television signal $I$. $03\,KHz$

$B$. Radio signal $II$. $20\,KHz$

$C$. High Quality Music $III$. $02\,MHz$

$D$. Human speech $IV$. $06\,MHz$

Choose the correct answer from the options given below:

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