The group displacement law was given by:

When ${}_{92}^{238}U$ (Group $III B$) changes to ${}_{90}^{234}Th$ by the emission of an $\alpha$-particle,the daughter element will be in which group?

$A$ nuclide of an alkaline earth metal undergoes radioactive decay by emission of two $\alpha$-particles in succession. The group of the periodic table to which the resulting daughter element would belong is $Group$ .......

$_{84}Po^{210} \xrightarrow{} _{82}Pb^{206} + _{2}He^{4}$. From the above equation,deduce the position of polonium in the periodic table (lead belongs to group $IV A$).

When a radium atom,which is placed in group $II$,loses an $\alpha$-particle,a new element is formed which should be placed in group ........

$A$ radioactive substance ${}_{88}X^{228}$ (Group $IIA$) emits $3 \alpha$ and $3 \beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?