Heating of 2-chloro-1-phenylbutane with EtOK/ | vedclass

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(A) Step $1$: Dehydrohalogenation of $2-$chloro$-1-$phenylbutane with $EtOK/EtOH$ (a strong base) proceeds via the $E2$ mechanism to form the more sta

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$1-$phenylbutan$-2-$ol

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(A) Step $1$: Dehydrohalogenation of $2-$chloro$-1-$phenylbutane with $EtOK/EtOH$ (a strong base) proceeds via the $E2$ mechanism to form the more stable conjugated alkene,$1-$phenylbut$-1-$ene $(X)$,as the major product.Step $2$: The reaction of $1-$phenylbut$-1-$ene $(X)$ with $Hg(OAc)_2/H_2O$ followed by $NaBH_4$ is an Oxymercuration-Demercuration $(OMDM)$ reaction.Step $3$: $OMDM$ follows the Markovnikov addition rule,where the $-OH$ group attaches to the more substituted carbon atom of the double bond.Step $4$: In $1-$phenylbut$-1-$ene $(Ph-CH=CH-CH_2-CH_3)$,the carbon at position $1$ is attached to a phenyl group,making it more substituted than the carbon at position $2$. Therefore,the $-OH$ group adds to the $C1$ position,yielding $1-$phenylbutan$-1-$ol as the major product $Y$.

Heating of $2-$chloro$-1-$phenylbutane with $EtOK/EtOH$ gives $X$ as the major product. Reaction of $X$ with $Hg(OAc)_2/H_2O$ followed by $NaBH_4$ gives $Y$ as the major product. $Y$ is

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