Highest oxidation state of manganese in fluor | vedclass

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(D) The ability of an element to exhibit a higher oxidation state depends on its ability to form multiple bonds with the central metal atom.Oxygen $(O

Vedclass · Accepted Answer

In covalent compounds fluorine can form single bond only while oxygen forms double bond

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(D) The ability of an element to exhibit a higher oxidation state depends on its ability to form multiple bonds with the central metal atom.Oxygen $(O)$ is capable of forming $p\pi-d\pi$ multiple bonds with transition metals,which stabilizes higher oxidation states.In contrast,Fluorine $(F)$ can only form single covalent bonds $(F-M)$ and cannot form multiple bonds.Therefore,oxygen can stabilize the $ 7$ oxidation state of manganese in $Mn_2O_7$,whereas fluorine can only stabilize up to the $ 4$ oxidation state in $MnF_4$.

Highest oxidation state of manganese in fluoride is $+4$ $(MnF_4)$ but highest oxidation state in oxides is $+7$ $(Mn_2O_7)$ because $..........$

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