The highest stable Mn fluoride is MnF_4,where | vedclass

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(B) The stability of higher oxidation states of transition metals is determined by the nature of the ligand.
Oxygen,being a small and highly electron

Vedclass · Accepted Answer

Oxygen has the ability to form multiple bonds.

Vedclass · Answer

(B) The stability of higher oxidation states of transition metals is determined by the nature of the ligand.
Oxygen,being a small and highly electronegative atom,has the ability to form multiple bonds (specifically $p\pi-d\pi$ back-bonding) with the transition metal.
This multiple bonding stabilizes the metal in its highest oxidation state,such as $Mn$ in $Mn_2O_7$ ($+7$ oxidation state).
In contrast,fluorine can only form single bonds with the metal,which is insufficient to stabilize the $+7$ oxidation state of $Mn$,limiting it to $MnF_4$.

The highest stable $Mn$ fluoride is $MnF_4$,whereas the highest $Mn$ oxide is $Mn_2O_7$. This is due to:

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