Hot liquids flow more easily than cold liquids. Give the reason.
(N/A) The viscosity of a liquid is defined by its coefficient of viscosity,denoted by $\eta$.
As the temperature of a liquid increases,the intermolecular forces of attraction decrease.
Consequently,the coefficient of viscosity $\eta$ decreases for hot liquids.
Since the viscous drag force between consecutive layers is given by $F = -\eta A \frac{dv}{dx}$,a lower value of $\eta$ results in a smaller viscous force.
Therefore,hot liquids experience less internal resistance and flow more easily than cold liquids.
As the temperature of a liquid increases,the intermolecular forces of attraction decrease.
Consequently,the coefficient of viscosity $\eta$ decreases for hot liquids.
Since the viscous drag force between consecutive layers is given by $F = -\eta A \frac{dv}{dx}$,a lower value of $\eta$ results in a smaller viscous force.
Therefore,hot liquids experience less internal resistance and flow more easily than cold liquids.
Explore More
Similar Questions
The flow of water in a river at the banks is slower than at the middle of the river. Explain.
Medium
View Solution$A$ square plate of side $0.1 \, m$ moves over another plate with a velocity of $0.1 \, m/s$ in a liquid of viscosity $0.01 \, poise$. If the viscous force acting is $0.002 \, N$,what is the distance between the two plates (in $, m$)?
Difficult
View Solution$A$ plastic circular disc of radius $R$ is placed on a thin oil film,spread over a flat horizontal surface. The torque required to spin the disc about its central vertical axis with a constant angular velocity is proportional to
Difficult
View Solution$Assertion :$ Machine parts are jammed in winter.
$Reason :$ The viscosity of lubricant used in machine parts increases at low temperatures.
$Reason :$ The viscosity of lubricant used in machine parts increases at low temperatures.
For the situation shown in the figure,water flows on the surface of a fixed plate. The velocity of water as a function of distance $y$ is given as: $u = \alpha \left[ \frac{y}{h} - 2\left( \frac{y}{h} \right)^2 \right]$. Determine the magnitude of the shear stress that the water applies at the base of the plate. The coefficient of viscosity is $\eta$.
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo