How do we differentiate between Fe^{3+} and C | vedclass

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(D) In group $III$ analysis,$Fe^{3+}$ and $Cr^{3+}$ are precipitated as hydroxides using $NH_4OH$ in the presence of $NH_4Cl$. $NH_4Cl$ provides $NH_4

Vedclass · Accepted Answer

Both $(b)$ and $(c)$

Vedclass · Answer

(D) In group $III$ analysis,$Fe^{3+}$ and $Cr^{3+}$ are precipitated as hydroxides using $NH_4OH$ in the presence of $NH_4Cl$. $NH_4Cl$ provides $NH_4^+$ ions,which suppress the dissociation of $NH_4OH$ due to the common ion effect,thereby decreasing the concentration of $OH^-$ ions. This ensures that only the hydroxides of group $III$ cations ($Fe^{3+}$,$Al^{3+}$,$Cr^{3+}$) precipitate,while preventing the precipitation of group $IV$ cations. $Fe(OH)_3$ forms a reddish-brown precipitate,whereas $Cr(OH)_3$ forms a green precipitate,allowing for their differentiation.

How do we differentiate between $Fe^{3+}$ and $Cr^{3+}$ in group $III$?

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