How far apart are the points (2,0,0) and (-3, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the points be $A = (2, 0, 0)$ and $B = (-3, 0, 0)$.Using the distance formula between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ in $3

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) Let the points be $A = (2, 0, 0)$ and $B = (-3, 0, 0)$.Using the distance formula between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ in $3D$ space:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$Substituting the values:$d = \sqrt{(-3 - 2)^2 + (0 - 0)^2 + (0 - 0)^2}$$d = \sqrt{(-5)^2 + 0 + 0}$$d = \sqrt{25} = 5$Thus,the distance between the points is $5$ units.

How far apart are the points $(2,0,0)$ and $(-3,0,0)$?

Similar Questions

The shortest distance of the point $(a, b, c)$ from the $X-$axis is:

Show that the points $P(-2, 3, 5)$,$Q(1, 2, 3)$,and $R(7, 0, -1)$ are collinear.

The distance of the point $(4, 3, 5)$ from the $y$-axis is

Find the distance between the following pairs of points: $(-1, 3, -4)$ and $(1, -3, 4)$.

Find the distance between the following pairs of points: $(2, 3, 5)$ and $(4, 3, 1)$. (in $\sqrt{5}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module