How many g of a dibasic acid (Mol. wt. = 200) | vedclass

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(A) For a dibasic acid,the equivalent weight $E$ is calculated as $E = \frac{	ext{Molecular weight}}{2} = \frac{200}{2} = 100 \ g/eq$.Decinormal stre

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(A) For a dibasic acid,the equivalent weight $E$ is calculated as $E = \frac{	ext{Molecular weight}}{2} = \frac{200}{2} = 100 \ g/eq$.Decinormal strength means the normality $N = \frac{1}{10} = 0.1 \ N$.The formula for normality is $N = \frac{W 	imes 1000}{E 	imes V(mL)}$,where $W$ is the weight in grams.Substituting the values: $0.1 = \frac{W 	imes 1000}{100 	imes 100}$.$0.1 = \frac{W 	imes 1000}{10000} \implies 0.1 = \frac{W}{10}$.$W = 0.1 	imes 10 = 1 \ g$.

How many $g$ of a dibasic acid (Mol. wt. $= 200$) should be present in $100 \ mL$ of its aqueous solution to give decinormal strength?

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