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(B) The biological nitrogen fixation reaction catalyzed by the nitrogenase enzyme is represented as follows:$N_2 + 8e^- + 8H^+ + 16ATP \longrightarrow

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Eight

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(B) The biological nitrogen fixation reaction catalyzed by the nitrogenase enzyme is represented as follows:$N_2 + 8e^- + 8H^+ + 16ATP \longrightarrow 2NH_3 + H_2 + 16ADP + 16\Pi$From the stoichiometry of the equation,it is evident that $16$ molecules of $ATP$ are required for the production of $2$ molecules of $NH_3$.Therefore,for the formation of $1$ molecule of $NH_3$,the number of $ATP$ required is $16 / 2 = 8$ $ATP$ molecules.

How many $ATP$ are required for the formation of one molecule of $NH_3$ by the nitrogenase enzyme?

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