How many sigma (sigma) and pi (pi) bonds are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Reimer-Tiemann reaction of phenol with $CHCl_3$ and $NaOH$ yields salicylaldehyde ($2$-hydroxybenzaldehyde) as the final product.The chemical

Vedclass · Accepted Answer

$15$ and $4$

Vedclass · Answer

(C) The Reimer-Tiemann reaction of phenol with $CHCl_3$ and $NaOH$ yields salicylaldehyde ($2$-hydroxybenzaldehyde) as the final product.The chemical formula of salicylaldehyde is $C_7H_6O_2$.Structure: $A$ benzene ring with an $-OH$ group at position $1$ and a $-CHO$ group at position $2$.Counting $\sigma$ bonds:- $6$ $C-C$ bonds in the ring.- $4$ $C-H$ bonds on the ring.- $1$ $C-O$ bond (phenolic).- $1$ $O-H$ bond.- $1$ $C-C$ bond (between ring and $-CHO$).- $1$ $C-H$ bond (in $-CHO$).- $1$ $C-O$ bond (in $-CHO$).Total $\sigma$ bonds = $6 + 4 + 1 + 1 + 1 + 1 + 1 = 15$.Counting $\pi$ bonds:- $3$ $\pi$ bonds in the benzene ring.- $1$ $\pi$ bond in the $C=O$ group.Total $\pi$ bonds = $3 + 1 = 4$.Thus,the number of $\sigma$ and $\pi$ bonds are $15$ and $4$ respectively.

How many $\sigma$ (sigma) and $\pi$ (pi) bonds are present respectively in the final product obtained by the Reimer-Tiemann reaction of phenol?

Similar Questions

At low temperature,phenol reacts with $Br_2$ in $CS_2$ to form:

The electrophile involved in the below reaction is:

How can phenol be converted to aspirin?

The order of stability of the conjugate base of the given acids is:
$(i)$ Phenol
(ii) $4-$Hydroxypyridine
(iii) Cyclohexanol

What is the correct order of $K_a$ values for the given compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module