How many enantiomer pairs are obtained by mon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The structure of $2, 3-$dimethylbutane is $CH_3-CH(CH_3)-CH(CH_3)-CH_3$. There are two types of equivalent hydrogens in this molecule: $1.$ Primar

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The structure of $2, 3-$dimethylbutane is $CH_3-CH(CH_3)-CH(CH_3)-CH_3$. There are two types of equivalent hydrogens in this molecule: $1.$ Primary hydrogens: Monochlorination at a primary carbon gives $ClCH_2-CH(CH_3)-CH(CH_3)-CH_3$ ($1-$chloro$-2, 3-$dimethylbutane). This molecule has one chiral center at $C-2$,so it exists as one pair of enantiomers ($d$ and $l$ forms). $2.$ Tertiary hydrogens: Monochlorination at a tertiary carbon gives $CH_3-CCl(CH_3)-CH(CH_3)-CH_3$ ($2-$chloro$-2, 3-$dimethylbutane). This molecule is achiral because it does not have a chiral center. Thus,only $1$ pair of enantiomers is obtained.

How many enantiomer pairs are obtained by monochlorination of $2, 3-$dimethylbutane?

Similar Questions

The starting substance for the preparation of $CH_3I$ is

Which product is obtained when bleaching powder is distilled with acetone?

Which one of the following reactions would be the best for the formation of $2-$bromobutane?
$(1)$ $CH_3CH=CHCH_2CH_3$ $\xrightarrow{HBr}$
$(2)$ $CH_3CH_2CH=CH_2$ $\xrightarrow{HBr}$
$(3)$ $CH_3CH=CHCH_3$ $\xrightarrow{Br_2}$
$(4)$ $CH_3CH_2CH=CH_2$ $\xrightarrow[Peroxide]{HBr}$

Alkyl halides are prepared from alcohols by treating with

Which among the following methods is $NOT$ suitable for the preparation of alkyl chlorides?

Vedclass Test Series

Exam Paper Generator

Online Exam Module