How many geometrical isomers are possible for | vedclass

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(B) The compound shown is $1$-bromo-$4$-methylcyclohexane. In substituted cyclohexanes,geometrical isomerism arises due to the relative orientation of

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The compound shown is $1$-bromo-$4$-methylcyclohexane. In substituted cyclohexanes,geometrical isomerism arises due to the relative orientation of the substituents above or below the plane of the ring. For $1,4$-disubstituted cyclohexane,the two substituents can be on the same side of the ring (cis-isomer) or on opposite sides of the ring (trans-isomer). Thus,there are $2$ possible geometrical isomers: $cis$-$1$-bromo-$4$-methylcyclohexane and $trans$-$1$-bromo-$4$-methylcyclohexane. Therefore,the correct option is $B$.

How many geometrical isomers are possible for the compound shown below?

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