How many geometrical isomers are possible for | vedclass

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Question

(B) The given compound is $1-ethyl-2-methylcyclohexane$.In a substituted cyclohexane ring,geometrical isomerism arises due to the relative orientation

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The given compound is $1-ethyl-2-methylcyclohexane$.In a substituted cyclohexane ring,geometrical isomerism arises due to the relative orientation of the substituents above or below the plane of the ring.For $1,2-disubstituted$ cyclohexane,the two substituents can be either on the same side $(cis)$ or on opposite sides $(trans)$ of the ring.Since the two substituents ($-CH_3$ and $-C_2H_5$) are different,the $cis$ and $trans$ forms are non-superimposable and distinct.Thus,there are $2$ geometrical isomers possible: $cis-1-ethyl-2-methylcyclohexane$ and $trans-1-ethyl-2-methylcyclohexane$.Therefore,the correct option is $B$.

How many geometrical isomers are possible for the compound shown below?

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