How many geometrical isomers are possible for | vedclass

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(C) The compound $C_2FClBrI$ corresponds to a substituted ethene where each carbon atom is bonded to two different halogen atoms. For an alkene of the

Vedclass · Accepted Answer

Six

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(C) The compound $C_2FClBrI$ corresponds to a substituted ethene where each carbon atom is bonded to two different halogen atoms. For an alkene of the type $abcC=Cde$,the number of geometrical isomers is determined by the arrangement of groups around the double bond. Since all four substituents $(F, Cl, Br, I)$ are different,we can fix the position of one atom (e.g.,$F$) on the first carbon and permute the others. Specifically,for $C_2FClBrI$,the number of geometrical isomers is $3! = 6$. The six possible isomers are shown in the provided image. Thus,there are $6$ geometrical isomers possible. Therefore,option $(c)$ is the correct answer.

How many geometrical isomers are possible for the compound with molecular formula $C_2FClBrI$?

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