How many grams of CaC_2O_4 (molecular mass = | vedclass

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(A) The dissociation of $CaC_2O_4$ is given by: $CaC_2O_{4(s)} \rightleftharpoons Ca^{2 }{(aq)}   C_2O_4^{2-}{(aq)}$Let the solubility be $S \ mol/L$.

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$0.0064$

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(A) The dissociation of $CaC_2O_4$ is given by: $CaC_2O_{4(s)} ightleftharpoons Ca^{2 }{(aq)}   C_2O_4^{2-}{(aq)}$Let the solubility be $S \ mol/L$. Then $K_{sp} = [Ca^{2 }][C_2O_4^{2-}] = S 	imes S = S^2$.Given $K_{sp} = 2.5 	imes 10^{-9}$,so $S^2 = 2.5 	imes 10^{-9}$.$S = \sqrt{2.5 	imes 10^{-9}} = \sqrt{25 	imes 10^{-10}} = 5 	imes 10^{-5} \ mol/L$.To find the mass in grams per litre,multiply the molar solubility by the molecular mass: $	ext{Mass} = S 	imes 	ext{Molecular mass} = 5 	imes 10^{-5} \ mol/L 	imes 128 \ g/mol$.$	ext{Mass} = 640 	imes 10^{-5} \ g/L = 0.0064 \ g/L$.

How many grams of $CaC_2O_4$ (molecular mass $= 128$) on dissolving in one litre distilled water will give a saturated solution (in $g$)? $[K_{sp}(CaC_2O_4) = 2.5 \times 10^{-9} \ mol^2 \ L^{-2}]$

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