How many grams of $Mg$ is required to completely reduce $100 \ mL$ of $0.1 \ M$ $NO_3^{-}$ solution using the following reaction:
$NO_3^{-} + Mg \longrightarrow Mg^{2+} + NH_3$

  • A
    $0.96$
  • B
    $0.62$
  • C
    $0.24$
  • D
    $0.75$

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