How many grams of residue is obtained by heat | vedclass

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(B) The thermal decomposition reaction of silver carbonate is: $Ag_2CO_3(s) 	o 2Ag(s) + CO_2(g) + 1/2 O_2(g)$.
Since $CO_2$ and $O_2$ are gases, the

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$2.16$

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(B) The thermal decomposition reaction of silver carbonate is: $Ag_2CO_3(s) 	o 2Ag(s) + CO_2(g) + 1/2 O_2(g)$.
Since $CO_2$ and $O_2$ are gases, the solid residue obtained is metallic silver $(Ag)$.
Molar mass of $Ag_2CO_3 = (2 	imes 108) + 12 + (3 	imes 16) = 216 + 12 + 48 = 276 	ext{ g mol}^{-1}$.
Number of moles of $Ag_2CO_3 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{2.76 	ext{ g}}{276 	ext{ g mol}^{-1}} = 0.01 	ext{ mol}$.
According to the stoichiometry of the reaction, $1 	ext{ mole}$ of $Ag_2CO_3$ produces $2 	ext{ moles}$ of $Ag$.
Therefore, moles of $Ag$ produced $= 2 	imes 0.01 	ext{ mol} = 0.02 	ext{ mol}$.
Mass of $Ag$ residue $= 	ext{moles} 	imes 	ext{molar mass} = 0.02 	ext{ mol} 	imes 108 	ext{ g mol}^{-1} = 2.16 	ext{ g}$.

How many grams of residue is obtained by heating $2.76 \text{ g}$ of silver carbonate (in $\text{ g}$)? (Given: Molar mass of $C$, $O$ and $Ag$ are $12$, $16$ and $108 \text{ g mol}^{-1}$ respectively)

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