How many grams of sodium (atomic mass = 23 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Wurtz reaction between methyl chloride and sodium metal in the presence of dry ether is represented by the equation:$2 CH_3Cl + 2 Na \xrightar

Vedclass · Accepted Answer

$46$

Vedclass · Answer

(D) The Wurtz reaction between methyl chloride and sodium metal in the presence of dry ether is represented by the equation:$2 CH_3Cl + 2 Na \xrightarrow{	ext{Dry ether}} CH_3-CH_3 + 2 NaCl$From the stoichiometry of the reaction,$2$ moles of sodium $(Na)$ are required to produce $1$ mole of ethane $(CH_3-CH_3)$.The molar mass of sodium is $23 \ g/mol$.Therefore,the mass of $2$ moles of sodium is $2 	imes 23 \ g = 46 \ g$.Thus,$46 \ g$ of sodium is required to prepare one mole of ethane.

How many grams of sodium $(atomic \ mass = 23 \ u)$ are required to prepare one mole of ethane from methyl chloride by the Wurtz reaction?

Similar Questions

One mole of an alkane $(x)$ requires $8$ mole oxygen for complete combustion. The sum of the number of carbon and hydrogen atoms in the alkane $(x)$ is . . . . . . .

How many chiral products are obtained upon the monochlorination of $2$-methylbutane?

Which of the following reactants is suitable for the preparation of methane and ethane by using one step only?

For the preparation of alkanes,an aqueous solution of sodium or potassium salt of carboxylic acid is subjected to:

Anhydrous sodium acetate on heating with sodalime gives

Vedclass Test Series

Exam Paper Generator

Online Exam Module