(B) The complex compound $[Co(NH_3)_6]Cl_3$ dissociates in an aqueous solution as follows:$[Co(NH_3)_6]Cl_3 \rightarrow [Co(NH_3)_6]^{3+} + 3Cl^-$From

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(B) The complex compound $[Co(NH_3)_6]Cl_3$ dissociates in an aqueous solution as follows:$[Co(NH_3)_6]Cl_3 \rightarrow [Co(NH_3)_6]^{3+} + 3Cl^-$From the dissociation,we get $1$ complex cation $[Co(NH_3)_6]^{3+}$ and $3$ chloride anions $Cl^-$.Total number of ions produced = $1 + 3 = 4$ ions.