How many minutes are required to deliver 3.21 | vedclass

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(D) The relationship between charge,current,and time is given by the formula: $Q = I 	imes t$Given:Charge $(Q) = 3.21 	imes 10^6 \ C$Current $(I) =

Vedclass · Accepted Answer

$107$

Vedclass · Answer

(D) The relationship between charge,current,and time is given by the formula: $Q = I 	imes t$Given:Charge $(Q) = 3.21 	imes 10^6 \ C$Current $(I) = 500 \ A$Substituting the values into the formula:$3.21 	imes 10^6 = 500 	imes t$Solving for time $(t)$ in seconds:$t = \frac{3.21 	imes 10^6}{500} = 6420 \ s$To convert the time into minutes:$t = \frac{6420}{60} \ min = 107 \ min$

How many minutes are required to deliver $3.21 \times 10^6$ Coulombs using a current of $500 \ A$ used in the commercial production of chlorine?

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