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(C) The total number of electrons in $N_2^+$ is $(7 + 7 - 1) = 13$ electrons.According to the molecular orbital theory,the electronic configuration fo

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$7$

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(C) The total number of electrons in $N_2^+$ is $(7 + 7 - 1) = 13$ electrons.According to the molecular orbital theory,the electronic configuration for $N_2^+$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^1$.The molecular orbitals filled with one or more electrons are: $\sigma 1s, \sigma^* 1s, \sigma 2s, \sigma^* 2s, \pi 2p_x, \pi 2p_y, \sigma 2p_z$.Counting these orbitals,we get a total of $7$ molecular orbitals.

How many molecular orbitals filled with one or more electrons are present in $N_2^+$?

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