How many molecules of methyl iodide are requi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of dimethylamine $(CH_3)_2NH$ with methyl iodide $(CH_3I)$ proceeds via nucleophilic substitution (Hofmann alkylation).Step $1$: $(CH

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The reaction of dimethylamine $(CH_3)_2NH$ with methyl iodide $(CH_3I)$ proceeds via nucleophilic substitution (Hofmann alkylation).Step $1$: $(CH_3)_2NH + CH_3I \rightarrow (CH_3)_3N + HI$Step $2$: $(CH_3)_3N + CH_3I \rightarrow (CH_3)_4N^{+}I^{-}$Thus,a total of $2$ molecules of methyl iodide are required to convert dimethylamine into tetramethylammonium iodide.

How many molecules of methyl iodide are required to obtain tetramethyl ammonium iodide from dimethyl amine?

Similar Questions

The major product obtained in the following reaction is:

Identify the reagent $R$ in the following reaction:
$C_6H_5NO_2 \xrightarrow{R} C_6H_5NHOH$

On prolonged heating of ammonium cyanate or urea,we get

The end product of the reactions is
$C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3} C$

Consider the following reaction. What is the major product formed?
$[CH_3CH_2CH_2-N^+(CH_3)_2-CH_2CH_3] OH^- \xrightarrow{\text{Heat}}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module