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(B) The structure of isopentane is $CH_3-CH(CH_3)-CH_2-CH_3$.There are $4$ distinct types of hydrogen atoms in isopentane:$1$. Primary hydrogens on th

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$4$

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(B) The structure of isopentane is $CH_3-CH(CH_3)-CH_2-CH_3$.There are $4$ distinct types of hydrogen atoms in isopentane:$1$. Primary hydrogens on the terminal $CH_3$ group attached to the $CH$ group.$2$. Tertiary hydrogen on the $CH$ group.$3$. Secondary hydrogens on the $CH_2$ group.$4$. Primary hydrogens on the terminal $CH_3$ group attached to the $CH_2$ group.Since there are $4$ different types of hydrogen atoms,replacing any one of them with a chlorine atom will result in $4$ different monochloro structural isomers.Therefore,the correct answer is $4$.

How many monochloro structural isomers are expected to be formed on free radical monochlorination of isopentane?

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