How many multiples of 5 are there from 10 to | vedclass

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(B) The sequence of multiples of $5$ from $10$ to $95$ forms an arithmetic progression where the first term $a = 10$,the last term $l = 95$,and the co

Vedclass · Accepted Answer

$18$

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(B) The sequence of multiples of $5$ from $10$ to $95$ forms an arithmetic progression where the first term $a = 10$,the last term $l = 95$,and the common difference $d = 5$. Using the formula for the $n^{th}$ term of an arithmetic progression: $l = a + (n - 1)d$. Substituting the values: $95 = 10 + (n - 1)5$. $85 = (n - 1)5$. $n - 1 = 17$. $n = 18$. Thus,there are $18$ multiples of $5$ in the given range.

How many multiples of $5$ are there from $10$ to $95$,including both $10$ and $95$?

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