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(D) To find the number of pairs of letters in the word $SEQUENTIAL$ that have as many letters between them as in the English alphabet,we check both fo

Vedclass · Accepted Answer

Four

Vedclass · Answer

(D) To find the number of pairs of letters in the word $SEQUENTIAL$ that have as many letters between them as in the English alphabet,we check both forward and backward directions:Word: $S, E, Q, U, E, N, T, I, A, L$Forward direction:$1$. $S$ to $U$: $S-(T)-U$ ($1$ letter between,same as alphabet)$2$. $E$ to $I$: $E-(F, G, H)-I$ ($3$ letters between,same as alphabet)$3$. $N$ to $L$: $N-(M)-L$ ($1$ letter between,same as alphabet)Backward direction:$4$. $L$ to $I$: $L-(K, J)-I$ ($2$ letters between,same as alphabet)Total pairs found: $4$ $(S-U, E-I, N-L, L-I)$.Therefore,the correct option is $D$.

How many pairs of letters are there in the word $SEQUENTIAL$ which have as many letters between them as are in the alphabet?

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