How many pairs of letters in the word BRIGHTE | vedclass

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(C) To find the number of pairs of letters in the word $BRIGHTER$ that have as many letters between them as in the English alphabet,we check both forw

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$3$

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(C) To find the number of pairs of letters in the word $BRIGHTER$ that have as many letters between them as in the English alphabet,we check both forward and backward directions:$1$. Forward direction:- $B$ to $R$: $B(C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q)R$ (No)- $R$ to $I$: $R(S, T, U, V, W, X, Y, Z, A, B, C, D, E, F, G, H)I$ (No)- $I$ to $G$: $I(H)G$ (No)- $G$ to $H$: $G, H$ (Adjacent in alphabet,$0$ letters between them. In the word,they are also adjacent. This is $1$ pair.)- $H$ to $T$: $H(I, J, K, L, M, N, O, P, Q, R, S)T$ (No)- $T$ to $E$: $T(U, V, W, X, Y, Z, A, B, C, D)E$ (No)- $E$ to $R$: $E(F, G, H, I, J, K, L, M, N, O, P, Q)R$ (No)$2$. Backward direction:- $R$ to $E$: $R(Q, P, O, N, M, L, K, J, I, H, G, F)E$ (No)- $E$ to $T$: $E(F, G, H, I, J, K, L, M, N, O, P, Q, R, S)T$ (No)- $T$ to $H$: $T(S, R, Q, P, O, N, M, L, K, J, I)H$ (No)- $H$ to $G$: $H(I)G$ (No)- $G$ to $I$: $G(H)I$ (Adjacent in alphabet,$0$ letters between them. In the word,they are also adjacent. This is $1$ pair.)- $I$ to $R$: $I(J, K, L, M, N, O, P, Q)R$ (No)- $R$ to $B$: $R(S, T, U, V, W, X, Y, Z, A)B$ (No)Wait,let's re-check carefully:- $B$ to $R$: $B(C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q)R$ (No)- $R$ to $I$: $R(S, T, U, V, W, X, Y, Z, A, B, C, D, E, F, G, H)I$ (No)- $I$ to $G$: $I, H, G$ (In alphabet $G, H, I$. $G$ and $I$ have $1$ letter $H$ between them. In the word $BRIGHTER$,$G$ and $I$ have $1$ letter $H$ between them. This is $1$ pair: $(G, I)$)- $G$ to $H$: $G, H$ (Adjacent,$0$ letters between. This is $1$ pair: $(G, H)$)- $H$ to $T$: $H(I, J, K, L, M, N, O, P, Q, R, S)T$ (No)- $T$ to $E$: $T(U, V, W, X, Y, Z, A, B, C, D)E$ (No)- $E$ to $R$: $E(F, G, H, I, J, K, L, M, N, O, P, Q)R$ (No)- $R$ to $E$: $R(Q, P, O, N, M, L, K, J, I, H, G, F)E$ (No)- $E$ to $T$: $E(F, G, H, I, J, K, L, M, N, O, P, Q, R, S)T$ (No)- $T$ to $H$: $T(S, R, Q, P, O, N, M, L, K, J, I)H$ (No)- $H$ to $G$: $H, G$ (Adjacent,$0$ letters between. This is $1$ pair: $(H, G)$)- $G$ to $I$: $G, H, I$ (In alphabet $G, H, I$. $G$ and $I$ have $1$ letter $H$ between them. In the word,$G$ and $I$ have $1$ letter $H$ between them. This is $1$ pair: $(I, G)$)- $I$ to $R$: $I(J, K, L, M, N, O, P, Q)R$ (No)- $R$ to $B$: $R(S, T, U, V, W, X, Y, Z, A)B$ (No)Total pairs: $(G, H), (G, I), (H, G), (I, G)$ are not all distinct. The pairs are $(G, H)$ and $(G, I)$.Actually,checking again: $G$ and $H$ are adjacent,$G$ and $I$ have $H$ between them. $H$ and $I$ are adjacent. $H$ and $G$ are adjacent. $I$ and $G$ have $H$ between them. $I$ and $H$ are adjacent.Pairs: $(G, H), (G, I), (H, I)$. Total $3$ pairs.

How many pairs of letters in the word $BRIGHTER$ have as many letters between them in the word as in the alphabet?

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