(D) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.For the expression to be defined,the denominator must not be zero,so $x - 1 \neq 0

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(D) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.For the expression to be defined,the denominator must not be zero,so $x - 1 \neq 0$,which implies $x \neq 1$.Adding $\frac{2}{x - 1}$ to both sides of the equation,we get $x = 1$.However,we have the condition $x \neq 1$ from the original equation.Since the only potential solution $x = 1$ is excluded by the domain of the equation,there are no roots.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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How many roots does the equation $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$ have?

IIT 1984 All IIT

A
One
B
Two
C
Infinite
D
None

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