How much kinetic energy will be gained by an | vedclass

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(A) The kinetic energy gained by a charged particle moving through a potential difference is given by the formula: $\Delta KE = q 	imes \Delta V$.An

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$40\,eV$

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(A) The kinetic energy gained by a charged particle moving through a potential difference is given by the formula: $\Delta KE = q 	imes \Delta V$.An $\alpha$-particle has a charge of $q = +2e$,where $e$ is the elementary charge.The potential difference between the two points is $\Delta V = V_1 - V_2 = 70\,V - 50\,V = 20\,V$.Substituting these values into the formula:$\Delta KE = 2e 	imes 20\,V = 40\,eV$.Therefore,the kinetic energy gained by the $\alpha$-particle is $40\,eV$.

How much kinetic energy will be gained by an $\alpha$-particle in going from a point at $70\,V$ to another point at $50\,V$?

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