How is the complete external and internal path completed for electron flow for a galvanic cell? Clarify it.
(N/A) In a galvanic cell,the flow of electrons is completed through two paths:
$1$. External Circuit: Electrons flow from the anode to the cathode through an external metallic wire. This flow is driven by the potential difference between the two electrodes.
$2$. Internal Circuit: The internal circuit is completed by a salt bridge or a porous membrane containing an electrolyte. This allows the movement of ions ($cations$ and $anions$) to maintain electrical neutrality in the half-cells and prevents the buildup of charge,thereby allowing the continuous flow of electrons.
$1$. External Circuit: Electrons flow from the anode to the cathode through an external metallic wire. This flow is driven by the potential difference between the two electrodes.
$2$. Internal Circuit: The internal circuit is completed by a salt bridge or a porous membrane containing an electrolyte. This allows the movement of ions ($cations$ and $anions$) to maintain electrical neutrality in the half-cells and prevents the buildup of charge,thereby allowing the continuous flow of electrons.
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