How is the cell constant determined?

  • A
    By measuring the resistance of the cell containing a solution of known conductivity.
  • B
    By measuring the resistance of the cell containing a solution of unknown conductivity.
  • C
    By measuring the length and area of the electrodes.
  • D
    By measuring the potential difference across the cell.

Explore More

Similar Questions

The resistance of a conductivity cell containing $0.001 \ M \ KCl$ solution at $298 \ K$ is $1500 \ \Omega$. What is the cell constant if the conductivity of $0.001 \ M \ KCl$ solution at $298 \ K$ is $0.146 \times 10^{-3} \ S \ cm^{-1}$?

What will be the concentration of a solution of an electrolyte if its molar conductivity and conductivity are respectively $230 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and $0.0115 \ \Omega^{-1} \ cm^{-1}$ at $298 \ K$ (in $M$)?

$0.0129 \ S \ cm^{-1}$ is equivalent to how many $S \ m^{-1}$ (in $S \ m^{-1}$)?

The molar conductivity of $0.02 \ M$ $KCl$ solution is $410 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $25^{\circ} C$. Calculate its conductivity?

Calculate the cell constant of a conductivity cell containing $0.01 \ M \ AgNO_3$ solution having a resistance of $1440 \ \Omega$ and a conductivity of $0.001262 \ \Omega^{-1} \ cm^{-1}$. (in $cm^{-1}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo