How can the ionic conductivity of an unknown solution be determined?

  • A
    By measuring the cell constant and resistance of the solution.
  • B
    By measuring the potential difference only.
  • C
    By measuring the current only.
  • D
    By measuring the volume of the solution.

Explore More

Similar Questions

Calculate the cell constant of a conductivity cell containing $0.1 \ M$ $KCl$ solution having a resistance of $60 \ \Omega$ and a conductivity of $0.014 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ} \ C$. (in $cm^{-1}$)

At $291 \ K$,a saturated solution of $BaSO_4$ was found to have a specific conductivity of $3.648 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and that of the water used is $1.25 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$. If the ionic conductances of $Ba^{2+}$ and $SO_4^{2-}$ are $110$ and $136.6 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively,the solubility of $BaSO_4$ at $291 \ K$ will be (Atomic masses: $Ba=137, S=32, O=16$)

Which of the following statements is incorrect with respect to metallic or electronic conductivity?

The specific conductance of $0.05 \ M$ $NaOH$ solution is $0.0115 \ S \ cm^{-1}$. What is its molar conductance $(\Lambda_{m})$ in $S \ cm^2 \ mol^{-1}$?

What is conductivity? On what factors does conductivity depend?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo