How can we convert a galvanometer into a voltmeter?

  • A
    By connecting a high resistance in series with the galvanometer.
  • B
    By connecting a low resistance in series with the galvanometer.
  • C
    By connecting a high resistance in parallel with the galvanometer.
  • D
    By connecting a low resistance in parallel with the galvanometer.

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Similar Questions

$A$ moving coil galvanometer of resistance $100 \ \Omega$ shows a full scale deflection for a current of $1 \ mA$. The value of shunt resistance required to convert this galvanometer into an ammeter, showing full scale deflection for a current of $5 \ mA$, is . . . . . . $\Omega$.

$A$ galvanometer of $100\,\Omega$ resistance gives full-scale deflection when $10\,mA$ of current is passed. To convert it into a $10\,A$ range ammeter,the resistance of the shunt required will be ............... $\Omega$.

$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

An ammeter gives full-scale deflection when a current of $2 \, A$ flows through it. The resistance of the ammeter is $12 \, \Omega$. If the same ammeter is to be used for measuring a maximum current of $5 \, A$,then the ammeter must be connected with a resistance of:

$A$ milliammeter of range $10\, mA$ and resistance $9\, \Omega$ is joined in a circuit as shown. The meter gives full-scale deflection for current $I$ when $A$ and $B$ are used as its terminals,i.e.,current enters at $A$ and leaves at $B$ ($C$ is left isolated). The value of $I$ is

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