What is the hybridisation of carbon C_2 and C | vedclass

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(D) The given molecule is $CH_3-CH=CH-CH_3$. Numbering the carbons from left to right: $C_1$ is $CH_3$ (attached to $C_2$ by a single bond). $C_2$ is

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$sp^2$ and $sp^3$

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(D) The given molecule is $CH_3-CH=CH-CH_3$. Numbering the carbons from left to right: $C_1$ is $CH_3$ (attached to $C_2$ by a single bond). $C_2$ is $CH$ (attached to $C_1$ by a single bond and $C_3$ by a double bond). $C_3$ is $CH$ (attached to $C_2$ by a double bond and $C_4$ by a single bond). $C_4$ is $CH_3$ (attached to $C_3$ by a single bond). For $C_2$: It is bonded to one $H$ atom,one $C_1$ atom (single bond),and one $C_3$ atom (double bond). It has $3$ sigma bonds and $0$ lone pairs,so it is $sp^2$ hybridised. For $C_4$: It is bonded to three $H$ atoms and one $C_3$ atom (single bond). It has $4$ sigma bonds and $0$ lone pairs,so it is $sp^3$ hybridised. Therefore,the hybridisation of $C_2$ and $C_4$ is $sp^2$ and $sp^3$ respectively.

What is the hybridisation of carbon $C_2$ and $C_4$ respectively in the molecule $CH_3-CH=CH-CH_3$?

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