Hydration of 3-phenylbut-1-ene in dil. H_2SO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The hydration of $3$-phenylbut$-1$-ene in dilute $H_2SO_4$ proceeds via the formation of a carbocation intermediate.$1$. Protonation of the double

Vedclass · Accepted Answer

$2$-Phenylbutan-$2$-ol

Vedclass · Answer

(C) The hydration of $3$-phenylbut$-1$-ene in dilute $H_2SO_4$ proceeds via the formation of a carbocation intermediate.$1$. Protonation of the double bond occurs to form a $2^{\circ}$ carbocation: $CH_3-CH(C_6H_5)-CH^+-CH_3$.$2$. This $2^{\circ}$ carbocation undergoes a $1,2$-hydride shift to form a more stable $3^{\circ}$ benzylic carbocation: $CH_3-CH_2-C^+(C_6H_5)-CH_3$.$3$. Finally,the nucleophilic attack of $H_2O$ on the $3^{\circ}$ carbocation followed by deprotonation yields $2$-phenylbutan-$2$-ol as the major product.

Hydration of $3$-phenylbut$-1$-ene in dil. $H_2SO_4$ will give mainly

Similar Questions

The major product of the following reaction is $CH_3-CH(Br)-CH_2-CH_3 + \text{alc. } KOH \to $

Product $B$ may be :

The product $(A)$ is:

Peroxide effect is observed with the addition of $HBr$ but not with the addition of $HI$ to unsymmetrical alkene because

How many propenyl radicals are possible from propene?

Vedclass Test Series

Exam Paper Generator

Online Exam Module