A hydrogen atom is excited from the ground st | vedclass

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(B) The number of spectral lines emitted when an electron transitions from an excited state with principal quantum number $n$ to the ground state is g

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The number of spectral lines emitted when an electron transitions from an excited state with principal quantum number $n$ to the ground state is given by the formula:$N = \frac{n(n - 1)}{2}$Given that the electron is excited to the state with principal quantum number $n = 4$,we substitute this value into the formula:$N = \frac{4(4 - 1)}{2}$$N = \frac{4 	imes 3}{2}$$N = \frac{12}{2} = 6$Therefore,the total number of spectral lines in the emission spectra is $6$.

$A$ hydrogen atom is excited from the ground state to another state with a principal quantum number equal to $4$. The number of spectral lines in the emission spectra will be:

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