Hydrogen combines with oxygen to form H_2O in | vedclass

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(A) According to the Law of Reciprocal Proportions,if two elements $C$ and $O$ combine separately with a third element $H$,then the ratio of their mas

Vedclass · Accepted Answer

$6 : 16$ or $3 : 8$

Vedclass · Answer

(A) According to the Law of Reciprocal Proportions,if two elements $C$ and $O$ combine separately with a third element $H$,then the ratio of their masses in which they combine with a fixed mass of $H$ is either the same or a simple multiple of the ratio in which they combine with each other.In $H_2O$,$2 \ g$ of $H$ combines with $16 \ g$ of $O$.In $CH_4$,$2 \ g$ of $H$ combines with $6 \ g$ of $C$.Therefore,the ratio of masses of $C$ and $O$ that combine with a fixed mass of $H$ $(2 \ g)$ is $6 : 16$.Simplifying $6 : 16$,we get $3 : 8$.

Hydrogen combines with oxygen to form $H_2O$ in which $16 \ g$ of oxygen combine with $2 \ g$ of hydrogen. Hydrogen also combines with carbon to form $CH_4$ in which $2 \ g$ of hydrogen combine with $6 \ g$ of carbon. If carbon and oxygen combine together then they will do so in the ratio of

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Which of the following pairs of compounds demonstrates the law of multiple proportions?

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