Hydrogen gas diffuses six times faster than g | vedclass

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(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$.Given that the rate of diffusion of hydrogen $(r_H)$ is $6$ times the rate of diffusion of gas $A$ $(r_A)$,we have $r_H = 6r_A$.The molar mass of hydrogen $(H_2)$ is $M_H = 2 \ g/mol$.Substituting these values into the formula: $\frac{r_H}{r_A} = \sqrt{\frac{M_A}{M_H}}$.$6 = \sqrt{\frac{M_A}{2}}$.Squaring both sides: $36 = \frac{M_A}{2}$.Therefore,$M_A = 36 	imes 2 = 72 \ g/mol$.

Hydrogen gas diffuses six times faster than gas $A$. The molar mass of gas $A$ is

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