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(D) $Hydrogen$ $peroxide$ $(H_2O_2)$ acts as a reducing agent when it reacts with strong oxidizing agents like $O_3$ or $KMnO_4$ in acidic medium.Howe

Vedclass · Accepted Answer

$Lead$ $sulphide$ suspension

Vedclass · Answer

(D) $Hydrogen$ $peroxide$ $(H_2O_2)$ acts as a reducing agent when it reacts with strong oxidizing agents like $O_3$ or $KMnO_4$ in acidic medium.However,$H_2O_2$ acts as an oxidizing agent when it reacts with $PbS$ (lead sulphide).The reaction is:$PbS(s) + 4H_2O_2(aq) 	o PbSO_4(s) + 4H_2O(l)$In this reaction,$PbS$ is oxidized to $PbSO_4$ and $H_2O_2$ is reduced to $H_2O$.

$Hydrogen$ $peroxide$ is reduced by:

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