Hydrogenation of naphthalene (P) with excess | vedclass

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Question

(B) Naphthalene $(P)$ consists of two fused benzene rings. When one ring is hydrogenated to form $1, 2, 3, 4-$ tetrahydronaphthalene $(Q)$,the remaini

Vedclass · Accepted Answer

one aromatic ring of $P$ is more reactive than the aromatic ring of $Q$

Vedclass · Answer

(B) Naphthalene $(P)$ consists of two fused benzene rings. When one ring is hydrogenated to form $1, 2, 3, 4-$ tetrahydronaphthalene $(Q)$,the remaining ring in $(Q)$ is a benzene ring. The aromaticity of the benzene ring in $(Q)$ makes it significantly more stable and less reactive towards further hydrogenation compared to the aromatic rings in naphthalene $(P)$. This difference in reactivity,where the aromatic ring of $(P)$ is more reactive than the aromatic ring of $(Q)$,is known as the annelation effect. Therefore,the correct conclusion is that one aromatic ring of $(P)$ is more reactive than the aromatic ring of $(Q)$.

Hydrogenation of naphthalene $(P)$ with excess hydrogen gas stops cleanly at $1, 2, 3, 4-$ tetrahydronaphthalene $(Q).$ What conclusion can be drawn from this experiment?

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