Hydrolysis of XeF_4 gives HF,O_2,Xe and 'X'. | vedclass

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(A) The hydrolysis reaction of $XeF_4$ is given by:$6XeF_4 + 12H_2O \longrightarrow 4Xe + 2XeO_3 + 24HF + 3O_2$Here,'$X$' is $XeO_3$.In $XeO_3$,the ce

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pyramidal

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(A) The hydrolysis reaction of $XeF_4$ is given by:$6XeF_4 + 12H_2O \longrightarrow 4Xe + 2XeO_3 + 24HF + 3O_2$Here,'$X$' is $XeO_3$.In $XeO_3$,the central atom $Xe$ has $8$ valence electrons. It forms $3$ double bonds with $O$ atoms and has $1$ lone pair.According to $VSEPR$ theory,the hybridization is $sp^3$ with one lone pair,resulting in a pyramidal geometry.

Hydrolysis of $XeF_4$ gives $HF$,$O_2$,$Xe$ and '$X$'. The structure of '$X$' is

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