Identify I, II, III in the given Born-Haber c | vedclass

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(B) The process $I$ represents the direct dissolution of the solid $AB(s)$ into its aqueous ions,which is the enthalpy of solution,$\Delta_{sol}H^o$.T

Vedclass · Accepted Answer

$\Delta_{sol}H^o, \Delta_{lattice}H^o, \Delta_{hyd}H^o$

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(B) The process $I$ represents the direct dissolution of the solid $AB(s)$ into its aqueous ions,which is the enthalpy of solution,$\Delta_{sol}H^o$.The process $II$ represents the breaking of the ionic lattice into gaseous ions,which is the lattice enthalpy,$\Delta_{lattice}H^o$.The process $III$ represents the hydration of gaseous ions to form aqueous ions,which is the enthalpy of hydration,$\Delta_{hyd}H^o$.According to Hess's Law,$\Delta_{sol}H^o = \Delta_{lattice}H^o + \Delta_{hyd}H^o$.Comparing this with the diagram:$I = \Delta_{sol}H^o$$II = \Delta_{lattice}H^o$$III = \Delta_{hyd}H^o$Therefore,the correct sequence is $\Delta_{sol}H^o, \Delta_{lattice}H^o, \Delta_{hyd}H^o$.

Identify $I, II, III$ in the given Born-Haber cycle diagram for the dissolution of an ionic solid $AB(s)$:
$AB(s) \xrightarrow{I} A^+(aq) + B^-(aq)$
$AB(s) \xrightarrow{II} A^+(g) + B^-(g)$
$A^+(g) + B^-(g) \xrightarrow{III} A^+(aq) + B^-(aq)$

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Identify $I, II, III$ in the given Born-Haber cycle diagram for the dissolution of an ionic solid $AB(s)$:$AB(s) \xrightarrow{I} A^+(aq) + B^-(aq)$$AB(s) \xrightarrow{II} A^+(g) + B^-(g)$$A^+(g) + B^-(g) \xrightarrow{III} A^+(aq) + B^-(aq)$