Identify 'X' in the following sequence of rea | vedclass

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(C) $1$. The reaction of benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$ with $CuCN/KCN$ (Sandmeyer reaction) yields benzonitrile $(P = C_6H_5CN)$.$2$.

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Benzyl alcohol

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(C) $1$. The reaction of benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$ with $CuCN/KCN$ (Sandmeyer reaction) yields benzonitrile $(P = C_6H_5CN)$.$2$. Reduction of benzonitrile $(C_6H_5CN)$ with $LiAlH_4$ gives benzylamine $(Q = C_6H_5CH_2NH_2)$.$3$. The reaction of primary aliphatic amine (benzylamine) with nitrous acid $(HNO_2)$ produces an unstable diazonium salt which decomposes to form benzyl alcohol $(X = C_6H_5CH_2OH)$.

Column-$I$	Column-$II$
$A$. Benzenesulphonyl chloride	$1$. Zwitter ion
$B$. Sulphanilic acid	$2$. Hinsberg reagent
$C$. Alkyl diazonium salts	$3$. Dyes
$D$. Aryl diazonium salts	$4$. Conversion to alcohols

Identify $'X'$ in the following sequence of reaction:
$C_6H_5N_2^+Cl^-$ $\xrightarrow{CuCN/KCN} P$ $\xrightarrow{LiAlH_4} Q$ $\xrightarrow{HNO_2} X$

Similar Questions

Identify $X$ and $Y$ in the following reaction: ${C_6H_5NH_2}$ $\xrightarrow[0^{\circ} - 5^{\circ}C]{NaNO_2 + 2HCl} X$ $\xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$

$C_6H_5NH_2 \xrightarrow{Br_2/CCl_4} ?$
What is the product?

The high melting point and insolubility in organic solvents of sulphanilic acid are due to its $......$ structure.

Which of the following compounds will not undergo an azo coupling reaction with benzene diazonium chloride?

Match the compounds given in Column-$I$ with the items given in Column-$II$.

Column-$I$ Column-$II$

$A$. Benzenesulphonyl chloride $1$. Zwitter ion

$B$. Sulphanilic acid $2$. Hinsberg reagent

$C$. Alkyl diazonium salts $3$. Dyes

$D$. Aryl diazonium salts $4$. Conversion to alcohols

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Identify $'X'$ in the following sequence of reaction:$C_6H_5N_2^+Cl^-$ $\xrightarrow{CuCN/KCN} P$ $\xrightarrow{LiAlH_4} Q$ $\xrightarrow{HNO_2} X$