Identify A to E in the given diagram. | vedclass

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Question

(B) In the given diagram of a flowering plant:$A$ points to the node,which is the region of the stem where leaves are borne.$B$ points to the internod

Vedclass · Accepted Answer

$A-Node, B-Internode, C-Bud, D-Primary root, E-Secondary root$

Vedclass · Answer

(B) In the given diagram of a flowering plant:$A$ points to the node,which is the region of the stem where leaves are borne.$B$ points to the internode,which is the portion of the stem between two nodes.$C$ points to the axillary bud,which develops in the axil of leaves and is capable of developing into a branch or flower.$D$ points to the primary root,which is the direct elongation of the radicle.$E$ points to the secondary root,which are the lateral branches of the primary root.Therefore,the correct identification is $A-Node, B-Internode, C-Bud, D-Primary root, E-Secondary root$.

Column-$I$	Column-$II$
$(a)$ Inferae	$(i)$ Hibiscus
$(b)$ Heteromerae	$(ii)$ Lemon
$(c)$ Bicarpellatae	$(iii)$ Sunflower
$(d)$ Thalamiflorae	$(iv)$ Madhuca
$(e)$ Calyciflorae	$(v)$ Catharanthus
	$(vi)$ Rose

Identify $A$ to $E$ in the given diagram.

Similar Questions

$Casuarina$ $equisetifolia$ is a

Mark the incorrect match.

Match the following columns based on Bentham and Hooker's classification system:

Column-$I$ Column-$II$

$(a)$ Inferae $(i)$ Hibiscus

$(b)$ Heteromerae $(ii)$ Lemon

$(c)$ Bicarpellatae $(iii)$ Sunflower

$(d)$ Thalamiflorae $(iv)$ Madhuca

$(e)$ Calyciflorae $(v)$ Catharanthus

$(vi)$ Rose

Which of the following is true for the $Heteromery$ series?

$A$. Citrus and Ricinus have synandrous condition.
$B$. In epitepalous condition,the cohesion occurs between tepal and filament of stamen.
$C$. Tetradynamous condition consists of two long and four short stamen filaments.

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