Identify A,B and C in the given reaction sequ | vedclass

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(B) The reaction sequence is as follows:$1$. $PbS$ (Galena) reacts with $HNO_3$ to form lead$(II)$ nitrate: $3PbS + 8HNO_3 \rightarrow 3Pb(NO_3)_2 + 2

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$PbS, PbSO_4, PbCrO_4$

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(B) The reaction sequence is as follows:$1$. $PbS$ (Galena) reacts with $HNO_3$ to form lead$(II)$ nitrate: $3PbS + 8HNO_3 \rightarrow 3Pb(NO_3)_2 + 2NO + 3S + 4H_2O$. Thus,$A = PbS$.$2$. $Pb(NO_3)_2$ reacts with $H_2SO_4$ to form lead$(II)$ sulfate precipitate: $Pb(NO_3)_2 + H_2SO_4 \rightarrow PbSO_4(s) + 2HNO_3$. Thus,$B = PbSO_4$.$3$. $PbSO_4$ is dissolved in ammonium acetate and acetic acid to form lead$(II)$ acetate,which then reacts with $K_2CrO_4$ to form a yellow precipitate of lead$(II)$ chromate: $PbSO_4 + 2CH_3COONH_4 \rightarrow Pb(CH_3COO)_2 + (NH_4)_2SO_4$ and $Pb(CH_3COO)_2 + K_2CrO_4 \rightarrow PbCrO_4(s) + 2CH_3COOK$. Thus,$C = PbCrO_4$.Therefore,$A = PbS$,$B = PbSO_4$,and $C = PbCrO_4$.

Identify $A$,$B$ and $C$ in the given reaction sequence.

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