Identify A in the following reaction: A + CH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of a Grignard reagent $(CH_3MgBr)$ with a carbonyl compound followed by acid hydrolysis $(H_3O^{+})$ produces an alcohol.In the given

Vedclass · Accepted Answer

Acetone

Vedclass · Answer

(D) The reaction of a Grignard reagent $(CH_3MgBr)$ with a carbonyl compound followed by acid hydrolysis $(H_3O^{+})$ produces an alcohol.In the given reaction,the product is tert-butyl alcohol,which is $(CH_3)_3C-OH$.Since the Grignard reagent provides one methyl group $(CH_3)$,the carbonyl compound $A$ must provide the remaining three-carbon skeleton with a carbonyl group.Acetone $(CH_3COCH_3)$ reacts with $CH_3MgBr$ to form an intermediate complex,which upon hydrolysis yields tert-butyl alcohol.The reaction is: $CH_3COCH_3 + CH_3MgBr$ $\rightarrow (CH_3)_3C-OMgBr$ $\xrightarrow{H_3O^{+}} (CH_3)_3C-OH + Mg(OH)Br$.Therefore,$A$ is Acetone.

Column-$I$ (Name)	Column-$II$ (Structure)	Column-$III$ (Source)
$(A)$ Vanillin	$(i)$ $C_6H_4(OH)CHO$ (ortho)	$(p)$ From cinnamon
$(B)$ Salicylaldehyde	$(ii)$ $C_6H_5CH=CHCHO$	$(q)$ From seeds of vanilla
$(C)$ Cinnamaldehyde	$(iii)$ $C_6H_3(OH)(OCH_3)CHO$	$(r)$ From meadow sweet

Identify $A$ in the following reaction: $A + CH_3MgBr$ $\xrightarrow{\text{ether}} \text{complex}$ $\xrightarrow{H_3O^{+}} (CH_3)_3C-OH$

Similar Questions

Which of the following compounds will not give "Iodoform" by reaction with "Sodium hypoiodite"?

What will be the order of reactivity of the following carbonyl compounds with a nucleophile?
$(I)$ $HCHO$
$(II)$ $CH_3CHO$
$(III)$ $(CH_3)_2CO$
$(IV)$ $(Me_3C)_2CO$

Product $(B)$ in this reaction is

The alkaline $CuSO_4$ solution containing sodium potassium tartrate does not react with:

Vedclass Test Series

Exam Paper Generator

Online Exam Module